the integral from 0 to phi of sin^2 theta d(theta)
=[theta/2 -sin(2theta)/4 ] from 0 to phi
Can you explain to me how to arrive the second step ? I don't get it ! Thank you very much.
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I will use x instead of phi.
Use the identity:
galactus gave the simplest way, another one could be
and apply integration by parts.
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