$\displaystyle \int{x^3cos^2(x^2)dx}=$ substitute: $\displaystyle u=x^2$,$\displaystyle du=2xdx$ $\displaystyle \frac{1}{2}\int ucos^2u du$ i need help solving this from here
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Use $\displaystyle \cos^2u=1-\sin^2u$ You'll have an integral to compute applying integration by parts. You can use too $\displaystyle \cos^2u=\frac12(1+\cos2u)$
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