# Math Help - a double integral question

1. ## a double integral question

use a double integral in polar coordinates to find the volume of the solid in the first octant bounded above by the surface z=rsin(theta) , below by the xy-plane, and laterally by the plane x=0 and the surface r=3sin(theta).

Thank you very much.

2. Hey KittyKat:

Here is the integral. See if you can do it in rect.

$\int_{0}^{\frac{\pi}{2}}\int_{0}^{3sin{\theta}}r^{ 2}sin({\theta})drd{\theta}=9\int_{0}^{\frac{\pi}{2 }}sin^{4}{\theta}d{\theta}$

3. Hi galactus,

Thanks! I got 27pi/6 . Am I correct?

4. 27pi/16