$\displaystyle \int\frac{x^2-x+1}{x^3+x}dx$

$\displaystyle \frac{x^2-x+1}{x(x^2+1)} = \frac{A}{x}+\frac{Bx+C}{x^2+1}$

$\displaystyle x^2-x+1 = A(x^2+1)+(Bx+C)X$

i plugged in $\displaystyle x=0$ and got $\displaystyle A=1$

need help finding $\displaystyle B$ and $\displaystyle C$