Area (S) is 2. How do I find the equation of this parabola? ;\

http://img846.imageshack.us/img846/3081/function.png

I guess first of all I should start at this:

$\displaystyle \int_{0}^1 ?? dx=2$ but it does not seem to help me at all...

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- Mar 16th 2011, 10:33 AMElllaFinding the equation of parabola
Area (S) is 2. How do I find the equation of this parabola? ;\

http://img846.imageshack.us/img846/3081/function.png

I guess first of all I should start at this:

$\displaystyle \int_{0}^1 ?? dx=2$ but it does not seem to help me at all... - Mar 16th 2011, 11:03 AMemakarov
If the function whose graph is this parabola is $\displaystyle f(x)=ax^2+bx+c$, you have three unknowns: a, b and c. You also have three equations: $\displaystyle \int_0^1f(x)\,dx=2$, f(0) = 0 and f(1) = 0.

- Mar 16th 2011, 11:20 AMTheChaz
In other words, we know that x = 0 and x = 1 are roots, so x and (x - 1) are factors. So your quadratic is of the form ax(x - 1)...