is it use same method to do differentiation between hyperbolic trigo and normaal trigo?
if the question ask d/dx(4sinh^5 3x) after i differentiate it, is the answer become 60 sinh^4 3x?
I suspect your text book will tell you that the derivative of sin(x) is cos(x), the derivative of cos(x) is -sin(x), the derivative of sinh(x) is cosh(x), and the derivative of cosh(x) is sinh(x).
No, the derivative of $\displaystyle 4 sinh^5(3x)$ is NOT $\displaystyle 60 sinh^4(3x)$. Nor is the derivative of $\displaystyle 4 sin^5(3x)$ equal to $\displaystyle 60 sin^4(3x)$.
The derivative of $\displaystyle 4sin^5(3x)$ is $\displaystyle 4(5)(sin^4(3x)$ times the derivative of $\displaystyle sin(3x)$ which is $\displaystyle 3 cos(3x)$. That is, the derivative of $\displaystyle 4sin^5(3x)$ is $\displaystyle 60sin^4(3x)cos(3x)$.
Now, back to you- what is the derivative of $\displaystyle 4 sinh^5(3x)$? What is the derivative of $\displaystyle 4 cosh^5(3x)$?