The question, as posted, doesn't make sense to me. The graph of the cubic, the x-axis, and x= 1 form a single region. I don't see what "y= 127" has to do with that.
Hey I have a calc exam Thursday and have been practicing for it. I came across this area problem that has me stumped, usually area is no problem for me but I can't seem to figure this one out.
I figured that you would break the area into two from 0 to 1 and 1 to 3 since the function and y=127 intersect at x=1 but when I went to integrate everything the computer told me that my answer was wrong. Please help
Hello, rawkstar!
Since you didn't show your work, we have no idea where your error is.
The graph looks like this:
Code:| 127+ * - - - - - - - * | .|:::::::::::::::| | .*|:::::::::::::::| | .*B:|::::::A::::::::| | .*::::|:::::::::::::::| - - * - - - + - - - + - - - + - | 1 2 3 |
Area is a 2-by-127 rectangle: .
Area requires an integral: .
We have: .
. . . . . . . .
Therefore, the total area is: .