-1/2 times the integral (from 0 to pi/2) of cos^4 theta - 2cos^2 theta d(theta) Thank you very much.
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Use power reduction formulas: and
hey turkeywilliam, I did. But I just can't get the right answer. I got (5pi)/64 +1/8 . But the correct answer is (5pi)/32. Don't know why?
Originally Posted by tukeywilliams Use power reduction formulas: and Originally Posted by kittycat hey turkeywilliam, I did. But I just can't get the right answer. I got (5pi)/64 +1/8 . But the correct answer is (5pi)/32. Don't know why? Expand the integrand in the first integral: Now use power reduction in the last integral again: Now try it. -Dan
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