Problem:

$\displaystyle e^{x/y} = x - y$

Solution attempt 1:

i) differentiate both sides of function,

$\displaystyle \frac{e^{x/y}(y-xy')}{y^2} = 1 -y'$

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- Mar 14th 2011, 06:48 PMFoxlionimplicit diff. step check
Problem:

$\displaystyle e^{x/y} = x - y$

Solution attempt 1:

i) differentiate both sides of function,

$\displaystyle \frac{e^{x/y}(y-xy')}{y^2} = 1 -y'$ - Mar 14th 2011, 07:00 PMTheChaz
Check! Now for some algebra...

- Mar 14th 2011, 11:49 PMmatheagle
Why don't you take the Log and work with $\displaystyle x=y\ln(x-y)$