differential equations

How would you do this:
solve:
y^2dy - 3x^5dx = 0
the answer in the book is 2y^3 = 3x^6 + C
I am clueless how to do these types of problems. The book doesnt explain it clearly and my notes arent helping me. Thanks.

So .

Then


Or

Let and we get



This is also separation of variables.

Quote:

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Originally Posted by davecs77

How would you do this:
solve:
y^2dy - 3x^5dx = 0
the answer in the book is 2y^3 = 3x^6 + C
I am clueless how to do these types of problems. The book doesnt explain it clearly and my notes arent helping me. Thanks.

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Exactly like the other one:



so:





Now multiply through by 6:



(the constant has now been replaced by the constant )

Reaarange and you have the result.

RonL