i want to find the critical point of the graph

i done that, but have difficulties then

f'(x)=4x^3+3x^2-36x+24

then f'(x)= 0 is critical point, but i don't know how to solve f'(x)=0.........

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- Mar 12th 2011, 11:58 AMjackoppcritical point of graph
i want to find the critical point of the graph

i done that, but have difficulties then

f'(x)=4x^3+3x^2-36x+24

then f'(x)= 0 is critical point, but i don't know how to solve f'(x)=0......... - Mar 12th 2011, 01:03 PMskeeter