i want to find the critical point of the graph

i done that, but have difficulties then

f'(x)=4x^3+3x^2-36x+24

then f'(x)= 0 is critical point, but i don't know how to solve f'(x)=0.........

Printable View

- Mar 12th 2011, 10:58 AMjackoppcritical point of graph
i want to find the critical point of the graph

i done that, but have difficulties then

f'(x)=4x^3+3x^2-36x+24

then f'(x)= 0 is critical point, but i don't know how to solve f'(x)=0......... - Mar 12th 2011, 12:03 PMskeeter