Problem:

Solution attempt:

Answer in book:

Notes:I've always had a mundane problem with negatives and fractions, when I cancel out the negs in the last step, must I also switch the signs of the proceeding variables as well?

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- Mar 10th 2011, 12:01 PMFoxlionimplicit differentiation
Problem:

Solution attempt:

Answer in book:

Notes:I've always had a mundane problem with negatives and fractions, when I cancel out the negs in the last step, must I also switch the signs of the proceeding variables as well? - Mar 10th 2011, 12:36 PMicemanfan
Your second to last step is correct. What you are doing when you "cancel out" the negatives is multiplying the fraction by . So you get . Then use the distributive property to arrive at the correct answer (the one in your book).

- Mar 10th 2011, 12:39 PMprofound

which matches your answer: - Mar 10th 2011, 12:45 PMFoxlion
case closed, thank you both