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Math Help - Need some help with L'Hopital's.

  1. #1
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    Need some help with L'Hopital's.

    lim_{x \to a} \dfrac{\sqrt{2a^3x-x^4}-a\sqrt[3]{a^2x}}{a-\sqrt[4]{ax^3}}

    Really no idea where to start with this. I think what's throwing me off is the a's. I know that they are constants but having a bit of trouble figuring out how to deal with them.

    I can get this far.. and I'm not even sure if it's right or not.

    lim_{x \to a} \dfrac{(2a^3x-x^4)^{1/2} - a(a^2x)^{1/3}}{a - (ax^3)^{1/4}}

    lim_{x \to a}  \dfrac{\dfrac{2a^3-4x^3}{\sqrt{2a^3x-x^4}}-\dfrac{a^3}{3(a^2x)^{3/4}}}{-\dfrac{3\sqrt[4]{ax^3}}{4x}}
    Last edited by qleeq; March 10th 2011 at 08:24 AM.
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  2. #2
    Senior Member Sambit's Avatar
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    Your problem title says about L'Hospital's rule which needs differentiation, and then you need to know how to differentiate. If you are stuck with the constants (ie. the [i]a[/a]'s), note that f'(ax)=af'(x)
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  3. #3
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    Do I even need L'Hopital's method for this? I know it was the equation published in his book but still..
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  4. #4
    Senior Member Sambit's Avatar
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    Recheck the differentiation for last term in numerator. The power should be 2/3; not 3/4. You can then put a in place of x.
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