intergrate

**homerb** · March 9th 2011, 07:52 PM

intergral of 3x/3x-2 dx

**mr fantastic** · March 9th 2011, 07:56 PM

Originally Posted by homerb

intergral of 3x/3x-2 dx

Note that $\displaystyle \frac{3x}{3x - 2} = \frac{(3x - 2) + 2}{3x - 2} = 1 + \frac{2}{3x - 2}$ .

**BAdhi** · March 9th 2011, 07:56 PM

$\frac{3x}{3x-2}=1+\frac{2}{3x-2}$

now it's easy to integrate

**homerb** · March 9th 2011, 08:00 PM

So, after that do i do u= 3x-2
du= 3 dx? or what is the next step?

**mr fantastic** · March 9th 2011, 08:03 PM

Originally Posted by homerb

So, after that do i do u= 3x-2
du= 3 dx? [snip]

Yes.

**homerb** · March 9th 2011, 08:07 PM

my answer comes to x+(2/3)ln[3x-2]+c, is that correct?

**BAdhi** · March 9th 2011, 08:19 PM

$x+\frac{2}{3}ln|3x-2|+c$

NOTE: differentiate and you can check your answer for yourself

Thread: intergrate