From (1) get and insert to (2)
and we can insert it to ellipse equation.
Can anyone help with this problem please? I understand the concept of the langrange multiplier but this ones stumping me.
F(x,y)=2x+y subject to the ellipse g(x,y)=X^2+25y^2=1
I have f(x,y)=2i-1j. g(x,y)=2xi+50yj
When I apply the lamb though I get 2=lambda 2x. Which means lambda=1/x which doesn't make sense.
Can anyone tell me where I am wrong with is one?