note that the two graphs intersect at y = 0 and y = 9
using the method of washers about the y-axis (that is the line x = 0) ...
The volume of the solid obtained by rotating the region enclosed byabout the line can be computed using the method of disks or washers via an integral
I got 86 but that's wrong... Also I cant find the boundaries. I know a=0 and when I graphed the functions, they cross at x=2 but that's not right....
I think I understand the problem . . .
The region enclosed by is revolved about the line
Find the volume using washers.
You didn't show any work, but I assume your set-up was way off.
The graph looks like this:
Code:| 9+ - - - - - * | *:| | *::*| | *::: | | *::::* | | *:::* | --*-----------+------ | 3
They wanted the volume found by "washers".
. . So we must work "sideways".
The two functions are: .
Edit: Too slow ... again!