f(x) = sqrt ( x^2 + (4x/x - 8)^2 )

thanks a lot for you help

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- Mar 9th 2011, 02:39 AMrcscan anybody help me find the derivative of this f(x)
f(x) = sqrt ( x^2 + (4x/x - 8)^2 )

thanks a lot for you help - Mar 9th 2011, 02:53 AMHallsofIvy
What have you

**tried**yourself? If you let $\displaystyle u= x^2$, $\displaystyle v= \frac{4x}{x- 8}$, and $\displaystyle w= v^2$, that function is $\displaystyle f(x)= (u+ v)^{1/2}$

You will need to use the power rule, the quotient rule, and the chain rule.