The intergral of (4-2x)^3 dx?
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substitute
Originally Posted by homerb The intergral of (4-2x)^3 dx? Use substitution: Let:
thats what I did and I got -1/8*(4-2x)^4 + c, but in the book says -2(x-4)^4, am I doing something wrong?
Your answer is correct.. its needs simplification.. Originally Posted by homerb thats what I did and I got -1/8*(4-2x)^4 + c, but in the book says -2(x-4)^4, am I doing something wrong? thats the same thing.. take -2 as a common factor in the numerator and simplify..
Thanks
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