# Total differential

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• March 7th 2011, 06:19 PM
Tron
Total differential
Imageshack - 32201349.png

Help, please .

I have the answer which is :
dz = (2xe
–xy – x2ye–xy)dx – x3e–xydy = xe–xy((2 – xy)dx – x2dy). Can you show me what step exactly do we take in order to get there. Thx
• March 7th 2011, 06:37 PM
topsquark
Quote:

Originally Posted by Tron
Imageshack - 32201349.png

Help, please .

I have the answer which is :
dz = (2xe
–xy – x2ye–xy)dx – x3e–xydy = xe–xy((2 – xy)dx – x2dy). Can you show me what step exactly do we take in order to get there. Thx

$\displaystyle z = f(x,y)$

Thus
$dz = f_x(x, y) dx + f_y(x, y) dy$

So what are the partial derivatives?

-Dan