The diagram shows part of the curves '$\displaystyle y^2=8x$' and $\displaystyle y=x^2$

a.) Find the coordinates of A ( A is where they intercept in the top right of the diagram)

b.) Calculate the volume generated when the area enclosed by the curve is rotated through 360(degrees) about the x axis.

I identified A to be (2,4).

Then to attempt the 'b' part of my question

$\displaystyle \pi$$\displaystyle \[ \int_0^2 [(x^2)-sqrt(8x))]^2 \,dx.\] $

Using this I get a result of $\displaystyle 8\pi/2$ which is incorrect. Wondering if you can see my error. Sorry for the lack of steps, I'm having difficulty with LATEX (I'm in the process of improving though).