Okay so here is the deal.

I have the function.

G(x)=(x^3-1)^3

G'(x)= 3 (x^3-1)^2 * 3x

And i need to find out where the function is increasing and decreasing. I know how to do that, I have to set it to zero to find the critical numbers. However, I have two questions I guess. One being is my first derv right, and then if it is....how to i solve for zero. Should I divide by 2x?? then 3?? I am confused.