Hi guys you can see my problem attaced to the pictuse + my attempt to solve it.

and my question is how I can go further from there.Attachment 21069

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- Mar 6th 2011, 10:56 AMRiazyDetermine the area enclosed by the curve y = cos ^2 fi
Hi guys you can see my problem attaced to the pictuse + my attempt to solve it.

and my question is how I can go further from there.Attachment 21069 - Mar 6th 2011, 11:02 AMAllanCuz
If you know what the curve looks like it becomes a bit easiar to evaluate the area. Look at cos^2 x - Wolfram|Alpha and let us know how you want to approach this now.

- Mar 6th 2011, 11:35 AMRiazy
If you can see my attempt, i would like if someone could complete and show me the euler step there, I want to learn how to solve this analytically. Thanks

- Mar 6th 2011, 11:45 AMSoroban
Hello, Riazy!

Quote:

Why involve complex variables? . . . Why not standard Trig identities?

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- Mar 6th 2011, 11:48 AMRiazy
Really helpfull, Soroban, Thanks a lot.

- Mar 7th 2011, 10:54 AMRiazy
Okay there is one thing I didnt understand, sorry but i dont consider this to be a bump as I have got my answer, but I would like to ask

how you got 1/8 into 1/16 I can see that you multiplied everything within the brackets with 2. but what about 1/16?

Thanks for answers! - Mar 7th 2011, 09:34 PMSammyS
What

**Soroban**did was to change 2 to 4/2, then factored out a 1/2 .