(d2y/dx2) + (dy/dx)^0.5 +y =0
In this equation is the degree 2 or cannot be said?
since after removing the fraction there will be both degree one and degree 2
of the derivative (d2y/dx2)
or do we only take the highest degree of the highest order?
(d2y/dx2) + (dy/dx)^0.5 +y =0
In this equation is the degree 2 or cannot be said?
since after removing the fraction there will be both degree one and degree 2
of the derivative (d2y/dx2)
or do we only take the highest degree of the highest order?
All right, it works out to be the same in the end. The degree of the differential equation is the highest number of derivatives that we take of the unknown function (in this case y), not the highest power as it would be if this were an algebraic equation. So the degree still ends up as being 2. (And my description of the type of equation is still accurate.)
-Dan