let x = z^3 dx = 3z^2dz im stuck here .... divide numerator by denominator im stuck at the integral of 12 / (2 + z^(1/2))
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Try taking x=z^6 then dx=6(z^5), substituting and then Simplyfying u will get 6z^3/(1+z) You can then divide and integrate as usual
thanks
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