Thread: Integration - Algebraic substitution

let x = z^3
dx = 3z^2dz




im stuck here
.... divide numerator by denominator


im stuck at the integral of 12 / (2 + z^(1/2))

Try taking

x=z^6

then dx=6(z^5),

substituting and then Simplyfying u will get

6z^3/(1+z)

You can then divide and integrate as usual

thanks