let x = z^3

dx = 3z^2dz

im stuck here

.... divide numerator by denominator

im stuck at the integral of 12 / (2 + z^(1/2))

Printable View

- Jul 31st 2007, 05:25 AM^_^Engineer_Adam^_^Integration - Algebraic substitution

let x = z^3

dx = 3z^2dz

im stuck here

.... divide numerator by denominator

im stuck at the integral of 12 / (2 + z^(1/2)) - Jul 31st 2007, 05:40 AMDili
Try taking

x=z^6

then dx=6(z^5),

substituting and then Simplyfying u will get

6z^3/(1+z)

You can then divide and integrate as usual - Jul 31st 2007, 05:44 AM^_^Engineer_Adam^_^
thanks