Let be the lamina in the plane enclosed by the curve and by the lines ; , i. e. ,
y ; ; ].
Given that the density p(x; y) of the lamina is given by , calculate the mass of the
lamina.
the substitution u could be used or otherwise.
Let be the lamina in the plane enclosed by the curve and by the lines ; , i. e. ,
y ; ; ].
Given that the density p(x; y) of the lamina is given by , calculate the mass of the
lamina.
the substitution u could be used or otherwise.
I think that integral you gave will give the density of the lamina, and we then have to find the surface area of it, then
however I'm not sure how you came to this integral and chose those limits, and do I have to apply to the inside integral and then to the result of the inside?
I drew the lamina and I think the upper and lower limit you chose for the inside uses the space between the straight lines and then on the outside integral I do not know how you chose but I know that the line meet the curve at
once I make that substitution and the integrand becomes
how do I solve the integral and also do I have to change the limits,
I think I have to integrate the inside one first w.r.t du then the outer one w.r.t dv?
limits of the inside will change using and the outer one will use