Relative extrema question

**Find the x-values of all points where the functions defined as follows have any relative extrema. Find the value(s) of any relative extrema.**

f(x)= x^3 + 3x^2 - 24x + 2

I did f'(x)= 3X^2 + 6X - 24

0= 3X^2 + 6X - 24 / 3

0=x^2 +2x-8

(x+4)(x-2) x=-4 and x= 2

I did a number line and picked -5, 0, and 3. I plug those numbers to the original problem and -5 came out to be a positive, 0 came out to be a negative, and 3 came out to be a positive.

f(-4)= (-4)^3 + 3(-4)^2 -24(-4) + 2= . Would -4 be my relative max?

f(2)= (2)^3 + 3(2)^2 -24(2) +2=-26. Would 2 be my relative min?