The problem is stated as follows:

---

Show that the equation defines z as a function of x and y near (1,1,1). Also show that (1,1) is a stationary point of this function and determine its kind.

---

The first part is easily shown with the implicit function theorem.

Differentiating the equation implicitly with respect to x:

, so gives near (x,y) = (1,1), and consequently, there.

Thus, (x,y) = (1,1) isn't a stationary point as the problem claims.

Feel free to point and laugh at me and tell me that (or preferably why) my arithmetic is wrong.