y= e^sin 2x Solution attempt: lny = sin 2x lny = 2sinxcosx
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For , let . Then, . Now, it is only a matter of substituting the values of and into the first equation at the top.
implicite differentiation. chain rule
Then, . Both of you have the correct answer, I get the use of the chain rule and it looks very clean but could you also use the product rule for ? Thus making did I just make a mistake?
Product rule applies when you have the form: . (which you don't have here) I am not sure where you are geting 2sin(2x)+2cos(2x) but if you will notice, the form of f(x) needing to use the chain rule is: where p(x)=sin(x) and q(x)=2x
Thank you integral, was confused as to which was the inside/ outside function. In fact I am rather ignorant of the transcendental functions altogether as I looked at sin2x as the product of sin and 2x.
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