y= e^sin 2x
lny = sin 2x
lny = 2sinxcosx
Follow Math Help Forum on Facebook and Google+
For , let . Then, .
Now, it is only a matter of substituting the values of and into the first equation at the top.
implicite differentiation. chain rule
Both of you have the correct answer, I get the use of the chain rule and it looks very clean but could you also use the product rule for ?
did I just make a mistake?
Product rule applies when you have the form: . (which you don't have here)
I am not sure where you are geting 2sin(2x)+2cos(2x) but if you will notice, the form of f(x) needing to use the chain rule is:
where p(x)=sin(x) and q(x)=2x
Thank you integral, was confused as to which was the inside/ outside function. In fact I am rather ignorant of the transcendental functions altogether as I looked at sin2x as the product of sin and 2x.
View Tag Cloud