Confused about partial fractions integration

**NOX Andrew** · March 1st 2011, 05:25 PM

The ultimate equation should be $1 = \dfrac{A}{x} + \dfrac{B}{x^2} + \dfrac{Cx + D}{x^2 - 1}$ .

**florx** · March 1st 2011, 05:31 PM

What happened to the 3 in front of x^2(x^2-1)?

**NOX Andrew** · March 1st 2011, 05:32 PM

You factored it out of the integral symbol, so you shouldn't include it in the partial fraction decomposition.

**topsquark** · March 1st 2011, 05:37 PM

Originally Posted by NOX Andrew

The ultimate equation should be $1 = \dfrac{A}{x} + \dfrac{B}{x^2} + \dfrac{Cx + D}{x^2 - 1}$ .

$\displaystyle 1 = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 1} + \frac{D}{x - 1}$

-Dan

**florx** · March 1st 2011, 05:41 PM

Originally Posted by topsquark

$\displaystyle 1 = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 1} + \frac{D}{x - 1}$

-Dan

Ah that way is much easier to find the variables. Thanks for your help guys.

**TheCoffeeMachine** · March 2nd 2011, 01:21 AM

Originally Posted by florx

Has the picture got edited out, or am the only person for whom it does not render?

Thread: Confused about partial fractions integration