Last edited by florx; Mar 1st 2011 at 05:33 PM.
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The ultimate equation should be $\displaystyle 1 = \dfrac{A}{x} + \dfrac{B}{x^2} + \dfrac{Cx + D}{x^2 - 1}$.
What happened to the 3 in front of x^2(x^2-1)?
You factored it out of the integral symbol, so you shouldn't include it in the partial fraction decomposition.
Originally Posted by NOX Andrew The ultimate equation should be $\displaystyle 1 = \dfrac{A}{x} + \dfrac{B}{x^2} + \dfrac{Cx + D}{x^2 - 1}$. $\displaystyle \displaystyle 1 = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 1} + \frac{D}{x - 1} $ -Dan
Originally Posted by topsquark $\displaystyle \displaystyle 1 = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 1} + \frac{D}{x - 1} $ -Dan Ah that way is much easier to find the variables. Thanks for your help guys.
Originally Posted by florx Has the picture got edited out, or am the only person for whom it does not render?