• Mar 1st 2011, 05:21 PM
florx
• Mar 1st 2011, 05:25 PM
NOX Andrew
The ultimate equation should be $\displaystyle 1 = \dfrac{A}{x} + \dfrac{B}{x^2} + \dfrac{Cx + D}{x^2 - 1}$.
• Mar 1st 2011, 05:31 PM
florx
What happened to the 3 in front of x^2(x^2-1)?
• Mar 1st 2011, 05:32 PM
NOX Andrew
You factored it out of the integral symbol, so you shouldn't include it in the partial fraction decomposition.
• Mar 1st 2011, 05:37 PM
topsquark
Quote:

Originally Posted by NOX Andrew
The ultimate equation should be $\displaystyle 1 = \dfrac{A}{x} + \dfrac{B}{x^2} + \dfrac{Cx + D}{x^2 - 1}$.

$\displaystyle \displaystyle 1 = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 1} + \frac{D}{x - 1}$

-Dan
• Mar 1st 2011, 05:41 PM
florx
Quote:

Originally Posted by topsquark
$\displaystyle \displaystyle 1 = \frac{A}{x} + \frac{B}{x^2} + \frac{C}{x + 1} + \frac{D}{x - 1}$

-Dan

Ah that way is much easier to find the variables. Thanks for your help guys.
• Mar 2nd 2011, 01:21 AM
TheCoffeeMachine
Quote:

Originally Posted by florx

Has the picture got edited out, or am the only person for whom it does not render?