Sorry this seems like such a simple problem, but I can't seem to get it simplified all the way. $\displaystyle y = (3/sinx) + (1/cotx)$
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Originally Posted by TenaciousE Sorry this seems like such a simple problem, but I can't seem to get it simplified all the way. $\displaystyle y = (3/sinx) + (1/cotx)$ $\displaystyle y = 3\csc{x} + \tan{x}$ $\displaystyle y' = -3\csc{x}\cot{x} + \sec^2{x}$