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Math Help - Limit

  1. #1
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    Limit

    I that the limit as x->2 of f(x)=(2x^2-8)/(x-2) is 8. But i don't understand how i get there, please help, i'm not really sure what i'm supposed to do

    *Has been edited to show the original question
    *Solved using factorising
    Last edited by stripe501; February 27th 2011 at 07:43 AM.
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  2. #2
    MHF Contributor FernandoRevilla's Avatar
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    Quote Originally Posted by stripe501 View Post
    I that the limit as x-> 0 of f(x)=(2x^2-8)/(x^2-4) is 8. But i don't understand how i get there, please help, i'm not really sure what i'm supposed to do
    Your function is continuous at x=0 so, the limit is f(0)=2 .
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  3. #3
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    Quote Originally Posted by stripe501 View Post
    I that the limit as x-> 0 of f(x)=(2x^2-8)/(x^2-4) is 8. no, it's not ... did you post the limit correctly?
    ...
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  4. #4
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    Never mind, I figured it out
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  5. #5
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    Yeah, I posted it wrong :/ thats why i couldn't get it
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