I that the limit as x->2 of f(x)=(2x^2-8)/(x-2) is 8. But i don't understand how i get there, please help, i'm not really sure what i'm supposed to do *Has been edited to show the original question *Solved using factorising
Last edited by stripe501; Feb 27th 2011 at 06:43 AM.
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Originally Posted by stripe501 I that the limit as x-> 0 of f(x)=(2x^2-8)/(x^2-4) is 8. But i don't understand how i get there, please help, i'm not really sure what i'm supposed to do Your function is continuous at so, the limit is .
Originally Posted by stripe501 I that the limit as x-> 0 of f(x)=(2x^2-8)/(x^2-4) is 8. no, it's not ... did you post the limit correctly? ...
Never mind, I figured it out
Yeah, I posted it wrong :/ thats why i couldn't get it
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