Thread: Limit

I that the limit as x->2 of f(x)=(2x^2-8)/(x-2) is 8. But i don't understand how i get there, please help, i'm not really sure what i'm supposed to do

*Has been edited to show the original question
*Solved using factorising

Originally Posted by stripe501

I that the limit as x-> 0 of f(x)=(2x^2-8)/(x^2-4) is 8. But i don't understand how i get there, please help, i'm not really sure what i'm supposed to do

Your function is continuous at so, the limit is .

Originally Posted by stripe501

I that the limit as x-> 0 of f(x)=(2x^2-8)/(x^2-4) is 8. no, it's not ... did you post the limit correctly?

...

Never mind, I figured it out

Yeah, I posted it wrong :/ thats why i couldn't get it