I that the limit as x->2 of f(x)=(2x^2-8)/(x-2) is 8. But i don't understand how i get there, please help, i'm not really sure what i'm supposed to do

*Has been edited to show the original question

*Solved using factorising

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- February 27th 2011, 06:26 AMstripe501Limit
I that the limit as x->2 of f(x)=(2x^2-8)/(x-2) is 8. But i don't understand how i get there, please help, i'm not really sure what i'm supposed to do

*Has been edited to show the original question

*Solved using factorising - February 27th 2011, 06:37 AMFernandoRevilla
- February 27th 2011, 06:39 AMskeeter
- February 27th 2011, 06:40 AMstripe501
Never mind, I figured it out :D

- February 27th 2011, 06:40 AMstripe501
Yeah, I posted it wrong :/ thats why i couldn't get it