What is the limit of the sequence Attachment 20973as n approaches infinity.

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- February 26th 2011, 04:02 PMjman919LImit with and exponent variable
What is the limit of the sequence Attachment 20973as n approaches infinity.

- February 26th 2011, 04:15 PMemakarov
Hint: .

- February 26th 2011, 06:06 PMjman919
Ok i understand how you got that.. but I'm not sure where to start. I keep getting that the limit is 1 which I know it is not.

- February 26th 2011, 06:19 PMNOX Andrew
Here is a useful equation:

.

For your problem, instead of evaluating the limit of the ratio, evaluate the ratio of the limits:

The limit in the denominator is 1. Division by 1 won't change anything, so the answer to your original problem is just the limit in the numerator.

If we let r = 2 and x = n + 1, then the limit in your problem becomes . Remember the useful equation at the top?

The limit is just e^r. Substituting r = 2 gives: e^2. - February 26th 2011, 07:34 PMjman919
Thank you so much , it makes sense now.

My mistake was not evaluating the numerator correctly. I found the limit of the denominator correctly, but for the numerator I said that the limit when n approaches infinity was = (1)^ infinity which is the same as 1. What was wrong with this reasoning? - February 26th 2011, 07:43 PMNOX Andrew
is what is called an indeterminate form. It's value cannot be determined. In this problem, it turns out it is "equal" to e^2. In another problem, it might turn out to be "equal" to sin(1). Some other common indeterminate forms are and . Here is a link to a Wolfram article on indeterminate forms: Indeterminate -- from Wolfram MathWorld

- February 26th 2011, 07:49 PMjman919
Oh , thats right. I completely forgot that it was indeterminate.