Please help me evaluate

e^(x)^1/2/ (x^1/2)

I started out with u substitution. First I let radical x be u, but I couldn't work it out properly because I didn't know what to cross out. Please give me some insight on this! (Wondering)

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- February 25th 2011, 11:17 AMkikiyaEvaluating an Integral
Please help me evaluate

e^(x)^1/2/ (x^1/2)

I started out with u substitution. First I let radical x be u, but I couldn't work it out properly because I didn't know what to cross out. Please give me some insight on this! (Wondering) - February 25th 2011, 11:20 AMTheEmptySet
- February 25th 2011, 11:21 AMpickslides
You're substitution is correct, what did you find to be?

Edit: TES beat me to the punch. - February 25th 2011, 11:24 AMpickslides
- February 25th 2011, 11:30 AMTheEmptySet
- February 25th 2011, 11:38 AMkikiya
I'm sorry, but where did you get the 2 that's outside of the integral? Please explain your process lol

- February 25th 2011, 11:58 AMpickslides
O.K given what do you get for ?

- February 25th 2011, 01:48 PMkikiya
Sorry I'm late but is it 1/ 2 (x^1/2) ?

- February 25th 2011, 02:25 PMNOX Andrew
Exactly. Unfortunately, there isn't a 1/2 inside the integral, so you can't substitute yet. Fortunately, you can place a 1/2 inside the integral as long as you place a 2 outside the integral (to balance the 1/2). Now, the problem looks like:

Substituting and gives:

- February 26th 2011, 03:06 AMHallsofIvy
Strictly speaking, what you wrote here was

but apparently you meant

which would be e^(x^(1/2))/x^(1/2)

Quote:

I started out with u substitution. First I let radical x be u, but I couldn't work it out properly because I didn't know what to cross out. Please give me some insight on this! (Wondering)

- February 26th 2011, 08:05 AMkikiya
Oh, I see the error! Thank you! :)

- February 26th 2011, 08:07 AMkikiya
Thank you for walking me through it! I was confiused about the balancing out, but now I get it! Thank you! :D