Hello all,

I'm in charge of finding the derivative of $\displaystyle 1 \over 4x-3$.

I first used the quotient rule, which came out to be

$\displaystyle 0 * (4x-3) - ((4x-3) * 1) \over (4x-3)^2$

and simplified to

$\displaystyle - 4x-3 \over (4x-3)^2$

However, this isn't complete. I understand that I need to use the chain rule on the numerator next, according to Wolfram-Alpha, but I don't understand why I need the chain rule since there's only 1 function. Can anyone shed some light on this?

Thank you in advance!