x = 6 √ t
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$\displaystyle \sqrt{t} = t^{1/2}$ Then you can use the power law as normal to find $\displaystyle \dfrac{dx}{dt}$
If $\displaystyle f(x) = \sqrt{g(x)}$, then $\displaystyle f'(x) = \frac{g'(x)}{2\sqrt{g(x)}}$. I find that very handy for both integration and differentiation.
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