# Differentiate with routes

• Feb 23rd 2011, 08:51 AM
john1875
Differentiate with routes
x = 6 √ t
• Feb 23rd 2011, 09:14 AM
e^(i*pi)
$\sqrt{t} = t^{1/2}$

Then you can use the power law as normal to find $\dfrac{dx}{dt}$
• Feb 23rd 2011, 10:40 AM
TheCoffeeMachine
If $f(x) = \sqrt{g(x)}$, then $f'(x) = \frac{g'(x)}{2\sqrt{g(x)}}$. I find that very handy for both integration and differentiation.