x = 6 √ t

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- Feb 23rd 2011, 08:51 AMjohn1875Differentiate with routes
x = 6 √ t

- Feb 23rd 2011, 09:14 AMe^(i*pi)
$\displaystyle \sqrt{t} = t^{1/2}$

Then you can use the power law as normal to find $\displaystyle \dfrac{dx}{dt}$ - Feb 23rd 2011, 10:40 AMTheCoffeeMachine
If $\displaystyle f(x) = \sqrt{g(x)}$, then $\displaystyle f'(x) = \frac{g'(x)}{2\sqrt{g(x)}}$. I find that very handy for both integration and differentiation.