I have the function

f(x) = (x^8)\ |x-2|

I have to determine if the function has a continuous extension at x=2 ???

My solution is

1- Lim (x-2)(x^2+2x+4)\(x-2)= 12 if x>or equal to 2

x goes to 2

2- Lim (x-2)(x^2+2x+4)\ - (x-2)= -12 if x less than 2

x goes to 2

Is there a continuous extension at x=2 ??????????????? although we have two values (12, -12) because of (absolute value) ??

or there is not continuous extension ??