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Thread: Finding integral:

  1. Feb 22nd 2011, 06:52 PM #1
    cwarga88
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    Finding integral:

    1/(xlnx)

    Step by step if you can please.
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  2. Feb 22nd 2011, 06:56 PM #2
    Prove It
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    \displaystyle \int{\frac{1}{x\ln{x}}\,dx} = \int{\frac{1}{\ln{x}}\,\frac{1}{x}\,dx}.

    Now make the substitution \displaystyle u =\ln{x} \implies \frac{du}{dx} = \frac{1}{x}.
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  3. Feb 22nd 2011, 06:56 PM #3
    TheCoffeeMachine
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    Hint: \displaystyle \int\frac{1}{x\ln{x}} \;{dx} = \int\frac{(\ln{x})'}{\ln{x}}\;{dx}.
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