Finding integral:

**cwarga88** · Feb 22nd 2011, 06:52 PM

1/(xlnx)

Step by step if you can please.

**Prove It** · Feb 22nd 2011, 06:56 PM

$\displaystyle \int{\frac{1}{x\ln{x}}\,dx} = \int{\frac{1}{\ln{x}}\,\frac{1}{x}\,dx}$ .

Now make the substitution $\displaystyle u =\ln{x} \implies \frac{du}{dx} = \frac{1}{x}$ .

**TheCoffeeMachine** · Feb 22nd 2011, 06:56 PM

Hint: $\displaystyle \int\frac{1}{x\ln{x}} \;{dx} = \int\frac{(\ln{x})'}{\ln{x}}\;{dx}$ .

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