I need some HW help again.
Let f(x) = 12x + 15 - 13e^x . Then the equation of the tangent line to the graph of f(x) at the point (0, 2) is given by y=mx+b where:
m = ?
For f'(x), I get: 12 - 13e^x
which I would think is the slope, but I can't get it to work out.