Find the values of x that give relative extrema for the function $\displaystyle f(x) = 3x^5 - 5x^3$

What is relative maximum and relative minimum of it?

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- Jul 26th 2007, 05:50 AM #1

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- Jul 26th 2007, 05:57 AM #2
I might not be right because I'm not sure why it says RELATIVE maximum and minimum, but to get the maximum and minimum of a function, differentiate it and set it equal to 0.

$\displaystyle f(x) = 3x^5 - 5x^3$

$\displaystyle \frac{dy}{dx} \ f(x) = 15x^4 - 15x^2 = 0$

$\displaystyle 0 = 15x^2(x^2 - 1) $

So $\displaystyle x = 1 \ or \ x = -1 \ or \ x = 0 $

- Jul 26th 2007, 05:58 AM #3

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- Jul 26th 2007, 06:06 AM #4

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- Jul 26th 2007, 06:08 AM #5

- Jul 26th 2007, 06:17 AM #6

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- Jul 26th 2007, 06:18 AM #7

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- Jul 26th 2007, 06:20 AM #8

- Jul 26th 2007, 06:22 AM #9

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- Jul 26th 2007, 06:41 AM #10

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- Jul 26th 2007, 06:47 AM #11

- Jul 26th 2007, 06:47 AM #12

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- Jul 26th 2007, 06:51 AM #13

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- Jul 26th 2007, 06:52 AM #14

- Jul 26th 2007, 06:53 AM #15

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