Using Derivitives, find the equation of the tangent line at the given point.
x/(x-1) at the point (2,2).
So I don't know whether to immediately use the quotient rule to find f'(x), then plug in x = 2 for f'(x). Am I going about this wrong?
Using Derivitives, find the equation of the tangent line at the given point.
x/(x-1) at the point (2,2).
So I don't know whether to immediately use the quotient rule to find f'(x), then plug in x = 2 for f'(x). Am I going about this wrong?
Yes, use y = mx + c (or + b... haven't seen that, but it could work!)
You should be able to replace all but the c with values, and solve to find the value of c. What role does m play? ... so you have it here by another name. Likewise y. And you know the value of x, of course. So deduce c.