A bullet is fired such that is follows a part given by x = 315t, y = 65t -4.9t^2

PART 1

Find the Magnitude and direction of the velocity with t-2.5 sec.

Vx = 315 and Vy = 40.5 with R=317.6 and Angle 7.3 degree.

PART 2

Now it asks find the time at which the bullet in this question would have a y component of 0, then find the the magnitude and firection of the velocity at that time. t>0

Answer is 321.6 and angle of -11.66 degree.

I am stuck on part 2 of this question. HELP, Thanks, Jo