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Math Help - Simple Linearization Problem

  1. #1
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    Simple Linearization Problem

    I must be losing my mind because I've been over and over this one and can't see what I am doing wrong:

    Find the linearization L(x) of the function f(x) = cos(x) at a = \frac{3\pi}{2}

    Here is what I have done:

    f'(x) = -sin(x)
    f'(\frac{3\pi}{2}) = -(-1) = 1

    L(x) = f(x) + f'(x)(x-a)
    L(x) = cos(\frac{3\pi}{2}) + 1(x - \frac{3\pi}{2})
    L(x) = 0 + x - \frac{3\pi}{2}
    L(x) = x - \frac{3\pi}{2}

    And that's my answer. But when I plug it into the web site, it gets kicked back as incorrect. Can anybody see my mistake? I can't!

    Thanks.

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  2. #2
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    first line should be L(x) = f(a) + f'(a)(x-a) ... other than that, looks fine to me. I do not attempt to understand the inner workings of online answering systems.
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  3. #3
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    Quote Originally Posted by skeeter View Post
    first line should be L(x) = f(a) + f'(a)(x-a) ... other than that, looks fine to me. I do not attempt to understand the inner workings of online answering systems.
    Personally, I hate those things!
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