The problem: prove that

$\displaystyle ArcTan(x)+ArcCot(x) = \Pi/2$

I am not sure how you "prove" this.

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- Feb 19th 2011, 07:13 PMskyd171Proof that two trig functions = Pi/2
The problem: prove that

$\displaystyle ArcTan(x)+ArcCot(x) = \Pi/2$

I am not sure how you "prove" this. - Feb 19th 2011, 07:21 PMmr fantastic
- Feb 19th 2011, 07:30 PMskyd171
Thanks.

- Feb 19th 2011, 07:52 PMProve It
- Feb 20th 2011, 03:22 AMHallsofIvy
Now that's going to confuse a lot of people, Prove It!

More generally, tan and cotan, sin and cos, sec and csc "swap" complementary angles. That is, if $\displaystyle \theta$ and $\displaystyle \phi$ are the two non-right angles in a right triangle, then [tex]tan(\theta)= cot(\phi), $\displaystyle sin(\theta)= cos(\phi)$, [tex], and $\displaystyle sec(\theta)= csc(\phi)$. And, of course, those two angles add to $\displaystyle \frac{\pi}{2}$ (did I get it right, Prove It?). - Feb 20th 2011, 03:35 AMProve It