Does anyone know how to graph this:
Inside r=a(1+cos pheta) and outside r=a cos pheta
Thanks!
Hello,
1. you have to switch your calculator to polar mode.
2. Enter the equations at r1 and r2 in the y-editor. You'll find the $\displaystyle \theta$ at the $\displaystyle \boxed{X,T,\theta,n}$-key of your calculator.
3. Use the following window-settings:
$\displaystyle \theta$min = 0
$\displaystyle \theta$max = 6.2831... the means it is 2$\displaystyle \pi$
$\displaystyle \theta$step = .1308996... that means it is $\displaystyle \frac{\pi}{24}$
xmin = -2
xmax = 5
xscl = 1
ymin = -3
ymax = 3
yscl = 1
4. I've attached the drawing.
5. I used a TI84 and I hope that the syntax is the same with a TI85. If not
Remark: Unfortunately the factor 2 is hidden by the cursor in the equation r1