If I know that:
$\displaystyle \frac{dk}{dl}=\frac{w}{v}$
Then does it follow that:
$\displaystyle dk=\frac{w}{v}dl$
$\displaystyle \int 1 dk=\frac{w}{v}\int1dl$
$\displaystyle \frac{k}{l}=\frac{w}{v}$
?
Thanks
What you have is:
$\displaystyle \displaystyle \dfrac{dk}{dl}=a$
This has solution
$\displaystyle k(l)=al+c$
Or to put it another way, you would have two arbitrary constants doing it your way. The sum and difference of arbitrary constants are both another arbitrary constant. That is the two constants are not equal.
CB