I think formula you have written is for volume, but I need a surface area. Formula for that in Cartesian coordinates is . That is from where my definite integral comes.
I think formula you have written is for volume, but I need a surface area. Formula for that in Cartesian coordinates is . That is from where my definite integral comes.
Thank you, Danny! I rechecked my calculus and found a mistakte. So the actual integrand is . And this is where I have stopped for now, because I cannot deal with this integrand either! Any ideas?
Thank you, Danny! I rechecked my calculus and found a mistakte. So the actual integrand is . And this is where I have stopped for now, because I cannot deal with this integrand either! Any ideas?
Let
You should be able to evaluate both of these easily (sin substitution should work).